All categories

3 years ago

Can somebody please help me out... I really don’t get it and no one seems to help...

Mathematics

2 answers:

babunello [35]3 years ago

6 0

I got you, just follow my work

-2x+3=-5x+9

-2x=-5x+6

3x=6

x=2

Plug x back in

-2(2)+3= -1

y=-1

FINAL ANSWER: (2,-1)

pickupchik [31]3 years ago

3 0

So remember the transitive property here:

"If a = b and a = c, then b = c"

In this case, since y = -2x + 3 and y = -5x + 9, this means that -2x + 3 = -5x + 9. Substitute -5x + 9 into y of the first equation to solve for x:

$-2x + 3 = -5x + 9$

Firstly, add 5x to both sides of the equation: $3x + 3 = 9$

Next, subtract 3 on both sides: $3x=6$

Lastly, divide both sides by 3 and your first answer will be $x=2$

Next, since we have the value of x, substitute it into either equation to solve for y as such:

$y=-2(2)+3\\y=-4+3\\y=-1\\\\y=-5(2)+9\\y=-10+9\\y=-1$

Putting it all together, your answer is (2,-1).

You might be interested in

How do you do this trig problem.

loris [4]

Consider a right triangle in which one of the angles $\theta$ satisfies

$\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35$

That is, the side opposite $\theta$ occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to $\theta$ then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

$\cos\theta=\dfrac45$

because

$\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1$

Then in this triangle,

$\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43$

7 0

3 years ago

Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every

Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

$A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}$