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levacccp [35]
3 years ago
15

What is the area (in square units) of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3 ?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

10 square units

Step-by-step explanation:

We want to find the area under the curve f(x)=x+3 from x=1 to x=3.

We use definite integrals to find this area.

\int\limits^3_1 {x+3} \, dx

We integrate to obtain:

\frac{x^2}{2}+3x|_1^3

We evaluate the limits to get:

\frac{3^2}{2}+3(3)-(\frac{1^2}{2}+3(1))

4.5+9-0.5-3=10

Therefore the area under the curve from x=1 to x=3 is 10 square unit.

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What is the solution of y= x squared - 10x + 16
PolarNik [594]

Answer:

The factor out of -10x + 16 is

-2(5x - 8)

Step-by-step explanation:

4 0
3 years ago
A square with diagonals is shown. the distance from one point to the middle point is x. the length from the center point to anot
Rina8888 [55]

The approximate value of x in the square that the diagonals meets to form four right angles is 5.7 units

<h3>Properties of a square.</h3>
  • All the sides are equal.
  • Opposite sides are parallel to each other.
  • The diagonal intersects at right angle.

Using Pythagoras theorem the value of x can be found as follows:

c² = a² + b²

where

  • c = hypotenuse
  • a and b are other legs

Therefore,

8² = x² + x²

64 = 2x²

x² = 64 / 2

x = √32

x = 5.65685424949

x = 5.7 units

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6 0
2 years ago
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(1 point) Suppose F⃗ (x,y)=⟨2y,−sin(y)⟩ and C is the circle of radius 3 centered at the origin oriented counterclockwise. (a) Fi
g100num [7]

Answer:

The required vector parametric equation is given as:

r(t) = <3cost, 3sint>

For 0 ≤ t ≤ 2π

Step-by-step explanation:

Given that

f(x, y) = <2y, -sin(y)>

Since C is a cirlce centered at the origin (0, 0), with radius r = 3, it takes the form

(x - 0)² + (y - 0)² = r²

Which is

x² + y² = 9

Because

cos²β + sin²β = 1

and we want to find a vector parametric equations r(t) for the circle C that starts at the point (3, 0), we can write

x = 3cosβ

y = 3sinβ

So that

x² + y² = 3²cos²β + 3²sin²β

= 9(cos²β + sin²β) = 9

That is

x² + y² = 9

The vector parametric equation r(t) is therefore given as

r(t) = <x(t), y(t)>

= <3cost, 3sint>

For 0 ≤ t ≤ 2π

8 0
3 years ago
Regina's mom bought her some bracelets. There were a total of 85 bracelets in 5 packages.
adelina 88 [10]
The answer your looking for is B
8 0
3 years ago
What is the measure of angle RSL if it is (9x+27)° and angle BSA is (6x+66)°
Shalnov [3]

Answer:

Assume:

(angle) RSB and angle (LSA) = D

and (line) ASR and (line) LSB is striaght then

(9x +27) + D = 180

(6x + 66) + D = 180

9x + D = 153

6x + D = 114

substitute

6x + D = 114

D = 114 - 6 x

9x + (114 - 6x) =153

3x = 39

x = 13

D = 114 - 6(13)

D=36


Step-by-step explanation:


8 0
3 years ago
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