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levacccp [35]
3 years ago
15

What is the area (in square units) of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3 ?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

10 square units

Step-by-step explanation:

We want to find the area under the curve f(x)=x+3 from x=1 to x=3.

We use definite integrals to find this area.

\int\limits^3_1 {x+3} \, dx

We integrate to obtain:

\frac{x^2}{2}+3x|_1^3

We evaluate the limits to get:

\frac{3^2}{2}+3(3)-(\frac{1^2}{2}+3(1))

4.5+9-0.5-3=10

Therefore the area under the curve from x=1 to x=3 is 10 square unit.

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Nicole needs to spend at least 4 hours each week practicing the guitar. She has already practiced 2 1/3 hours this week. She wan
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A lay came to the market to sell eggs . We first customer bought 1/2 of all her eggs and 1/2 of an egg. Her second customer boug
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Given:

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.

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The number of egg the lady have when she came to the market.

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Let x be the number of egg that the lady have when she came to the market.

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\text{Remaining eggs}=\dfrac{x}{2}-\dfrac{1}{2}-(\dfrac{x}{2}-\dfrac{1}{2})\times \dfrac{1}{2}-\dfrac{1}{2}

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=(\dfrac{x}{2}-\dfrac{x}{4})+(-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{2})

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