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Ber [7]
4 years ago
10

Find the value of k if it is known that the line y=kx+2 goes through point:

Mathematics
1 answer:
MrRissso [65]4 years ago
3 0

Answer:

k = -10/7 and k = -3

Step-by-step explanation:

Given: <em>y</em> = <em>kx</em> + 2

where k is the slope of line and 2 is y-intercept.

∵ line <em>y</em> = <em>kx </em>+ 2 is passing through point <em>P</em> (-7, 12), ∴ <em>x</em> = -7 and <em>y </em>= 12

Now substituting the value of x and y in above equation,

<em>y </em>= <em>kx</em> + 2

12 =<em> k</em>(-7) + 2

-7<em>k</em> = 12 - 2

- 7<em>k</em> = 10

k = \frac{-10}{7}

In the same way, ∵ line <em>y</em> = <em>kx </em>+ 2 is passing through point <em>P</em> (3, -7), ∴ <em>x</em> = 3 and <em>y </em>= -7

<em>y </em>= <em>kx</em> + 2

Now substituting the value of x and y in above equation,

-7 =<em> k</em>(3) + 2

<em>3k</em> = -7 - 2

<em>3k</em> = - 9

<em>k</em> = -3

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