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3 years ago

PLEASE HELPPP!!!!!!!

Mathematics

1 answer:

Rudik [331]3 years ago

3 0

The answer is 11 because if you look at the chart. You can see everything can be divided by 8 and 88 divided by 8 is 11.

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seropon [69]

Answer

Step-by-step explanation:

4 0

3 years ago

With my math and it has strawberries and grapes

kvv77 [185]

Answer:

9 total

3 strawberries

6 blueberries

Step-by-step explanation:

We have 9 berries

3 are strawberries

9-3 = 6

That leaves 6 to be blueberries

9 total

3 strawberries

6 blueberries

3 0

3 years ago

Read 2 more answers

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andrew-mc [135]

For the reaction,

$CO(g) + H_2 O(g) = CO_2(g) + H_2(g)$

Initial concentration:

0.1M , 0.1M , 0 , 0

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

(0.1 – x)M , (0.1 – x)M , xM , xM

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

$K_c = \frac{x²}{(0.1 – x)²} = 4.24$

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

a = 3.24, b = -0.848, c = 0.0424

(for quadratic equation ax² + bx+c=0)

$x = \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}$

$= > x = \frac{ - ( - 0.848 \: ± \: \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}$

$= > x = \frac{ - 0.848±0.4118}{6.48}$

$x_1 = \frac{0.848 - 0.4118}{6.48} = 0.067$

$x_2 = \frac{0.848 + 0.4118}{6.48} = 0.194$

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

$[CO_2] [H_2] = x = 0.067M$

$[CO] [H_2 O] = 0.1 - 0.067 = 0.033M$

7 0

3 years ago

P(A) = 0.33, P(A and B) = 0.25, find P(B

motikmotik

Answer:

≈0.76

Step-by-step explanation:

P(A) = 0.33

P(A and B) = 0.25

P(B) = ?

-------------

Probability of two events happening is the product of individual probabilities

P(A and B) = P(A)×P(B)

Then to find the probability of one of the events:

P(B) = P(A and B) / P(A)
P(B) = 0.25 / 0.33 ≈ 0.76

6 0

3 years ago

Sum to n terms the series 7 +77 +777

julia-pushkina [17]

Answer:

Step-by-step explanation:

=7 (1+11+111+1111......n)

=7/9 (9+99+999+9999....n)

=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)

=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))

=7/9 ((10 (10^n-1)/(10-1))-n)

4 0

3 years ago