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2 years ago

PLEASE HELPPP!!!!!!!

Mathematics

1 answer:

Rudik [331]2 years ago

3 0

The answer is 11 because if you look at the chart. You can see everything can be divided by 8 and 88 divided by 8 is 11.

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Solve the problem. The systolic blood pressures of the patients at a hospital are normally distributed with a mean of 136mm Hg a

shtirl [24]

we know that the 90 percentile in Z-score is ≈ 1.28 then,
=136 ± 1.28(13.8)
=(118.336 , 153.664)
hope it helps

6 0

3 years ago

Which statements are true regarding the prism? Check all that apply

denis-greek [22]

What are the choices

8 0

3 years ago

Lester's Cafe offers two kinds of espresso: single-shot and double-shot. Yesterday afternoon, the cafe sold 80 espressos in all,

bogdanovich [222]

Answer:

64 single-shot espressos

Step-by-step explanation:

Let's say that the cafe sold x single-shot espressos. The total number of espressos sold was 80, and 80% of that total 80 were single-shot. So, we have the equation:

x = 80% * 80

Remember that % just means "out of 100". So, 80% = 80/100:

x = (80/100) * 80 = 6400/100 = 64 single-shot espressos

Hope this helps!

7 0

3 years ago

Read 2 more answers

PLEASe HELP I DONT WANT TO WASTE MY POINTS

QveST [7]

Answer:

4 or 5

Step-by-step explanation:

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3 years ago

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For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago