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Hatshy [7]
3 years ago
8

What is 208 + 569 = and what's a estimate

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0
An estimate is a guess you make by using what you already know and applying with something new.

208+569= 777
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Yes because she has collected 902 you have to add the two numbers
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Solve the linear system using substitution. Show your work.<br> y = -3x + 3<br> 4x +3y = -1
marishachu [46]
Sub y in the second equation by y in the first equation:
We get 4x+3(-3x+3)=-1
4x-9x+9=-1
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y=-3(2)+3
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3 years ago
Read 2 more answers
Please help! ASAP thank you
Vlada [557]
X=8
The reason is because the red figure is just a dilation of the yellow figure.
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4 0
3 years ago
The Quadratic equation y=0.5(x-1)(x-n) has an x - intercept at (1,0) and a vertex at (-2,4.5). what is the value of n A -5 B -2
andre [41]

Step-by-step explanation:

the point being that a quadratic equation has 2 x-intercepts (or solutions of x for y = 0).

the advantage of this nice form the equation is written in is, that we see immediately both conditions, when y can be 0 : one of the bracket expressions must be 0.

so, the point (1, 0) covers (x-1).

we get the solution for (x-n), when we consider that such a quadratic function is simply a parabola and is symmetric around its vertex point.

the x value of the vertex (-2) tells us, that it is 3 units on the left side of the (1, 0) x-intercept point.

due to the symmetry of the curve the second x-intercept point must be even further to the left with additional 3 units distance in x direction.

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and A is the correct answer option.

8 0
3 years ago
The Police Department is investigating the need for a speed camera to be implemented on Swift Road. A sample of 60 cars passing
prisoha [69]

Answer:

Step-by-step explanation:

(a) Approximate the population standard deviation (?) with the sample standard deviation (s)

Approximate the standard normal distribution with the Student's t distribution

--------------------------------------------------------------------------------------------------------------------------------

(b) The degree of freedom =n-1=60-1=59

Given a=0.1, t(0.05, df=59) =1.67 (from student t table)

So the lower bound is

xbar -t*s/vn =41 -1.67*3/sqrt(60) =40.35

So the upper bound is

xbar +t*s/vn =41 +1.67*3/sqrt(60) =41.65

8 0
3 years ago
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