What is the sum of ten terms of an infinite geometric series if the first term is 8 and the ratio is 1/2
1 answer:
Answer:
We use the formula:
S 10 = 8 · [(1/2)^9 - 1] / (1/2 - 1 );
Then, S 10 = 8 · ( 1/512 - 1 ) / ( 1/2 - 1 );
S 10 = 8 · ( - 511 / 512 ) / (-1 / 2 );
S 10 = ( - 511 / 64 ) · ( - 2 );
S 10 = + 511 / 32;
S 10 = 15.96;
Step-by-step explanation:
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