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Jobisdone [24]
3 years ago
9

What is the GCF of 96x" and 642?? O 322 O 32 O 32 O 322

Mathematics
1 answer:
n200080 [17]3 years ago
3 0

The answer would be 32

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I DONT GET THIS: What is the Domain and Range of the function in context?
Anettt [7]

Answer:

c

Step-by-step explanation:

the domain is every possible input value and the range is every possible output value. since the outputs are all positive, the range is equal to all real numbers. and since the graph starts at 1,000, the domain is greater than or equal to 1,000

6 0
3 years ago
Line segment BC will be reflected over line m to form line segment BC. Which of the following statements must be true?
Len [333]

Answer:

<u>Option A</u>

Step-by-step explanation:

To reflect line segment BC over line m, BB' will be perpendicular to the line m

and line m bisector of BB'.

<u>So, the correct answer is option A</u>

A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'

<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.

<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.

7 0
3 years ago
Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0
3 years ago
Martha has $180. She needs a total of $2,000 to start investing in stocks. She earns $60 per day working, of which she saves $50
DIA [1.3K]
So she earns $60 per day working, but only saves $50. To solve this equation you have to multiply $50 to each day she works. If the total has to be exactly $2,000 then you must multiply 50 x 36.4 and that equals $2,000.
Your answer should be 36.4 days.
4 0
4 years ago
Which fraction and decimal forms match the long division problem?
kolbaska11 [484]

Answer:

Option B and D .....

If the provide option is correct

Or else it should be 7/9 and 0.777

mark me as brainliest ❤️

4 0
3 years ago
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