Answer:
1) (c)∠ G = 34°
2) (a) x = 33°
3) (d) The perpendicular segments are JM, KL, PQ AND NR.
Step-by-step explanation:
Here in the given questions:
1) p II r
⇒ ∠ G = 34° (ALTERNATE EXTERIOR ANGLES)
Hence, the measure of ∠ G = 34°
2) In the given triangle:
The measure of exterior angle is always the sum of interior opposite angles.
⇒ Here, x + 72° = 105°
or, x = 105° - 72° = 33° , or x = 33°
3) The given plane in the cube is JKPN
The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.
Hence, the segments are JM, KL, PQ AND NR.
The answer is A because there are only acute angles
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
tanx = 
Consider the left side
← divide terms on numerator/denominator by cotA
= 
= 
= right side , thus proven
Hi there! 9.125 * 10^-3 is definitely less than 9.125 * 10^2, because when it comes to negative powers of 10, the numbers are decimals. 10^-3 equals 0.001 or one thousandths in word form. 10^2 is 100. When solving for the answers. 0.009125 is less than 912.5. When 912.5 is divided by 0.009125 912.5 is 100^5 or 100,000 times greater than 0.009125. The answer is that 9.125 * 10^-3 is 100,000 (100^5) times less than 9.125 * 10^2.
