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Tasya [4]
3 years ago
9

How to decompose the number 5

Mathematics
2 answers:
Margarita [4]3 years ago
8 0
There are many ways to get the answer of 5:
0+5=5
1+4=5
2+3=5
3+2=5
4+1=5
5+0=5
vladimir2022 [97]3 years ago
6 0


There will be 6 ways to decompose the number 5

5️⃣+0️⃣
4️⃣+1️⃣
3️⃣+2️⃣
2️⃣+3️⃣
1️⃣+4️⃣
0️⃣+5️⃣
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A store sells cards on each of which there are drawing of different flowers: either roses, either daisies, either tulips, either
valkas [14]

The greatest number of different cards based on the permutations is 144.

<h3>How to compute the value?</h3>

From the information given, there are 4 versions which are either roses, daisies, tulips, or sunflowers and this is further divided into either Happy birthday, anniversary, or holidays.

Therefore, the greatest number of different cards will be:

= 4! × 3!

= 24 × 6

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7 0
1 year ago
Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.
dusya [7]

\huge\color{black}\underline\mathbb{\:ANSWER}

\green{••••••••••••••••••••••••••••••••••••••••••••••••••}

Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.

x = −5

x = 6

<h2>x = −6</h2>

therefore the answer is

<h2>x = −6</h2>

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4 0
2 years ago
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What number can go into 21 and 27
astra-53 [7]

3 only

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Find the H.C.F of the following expressions.
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Step-by-step explanation:

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5 0
3 years ago
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
2 years ago
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