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2 years ago

Lin runs 5 laps around a track in 6 minutes.

Mathematics

1 answer:

Paladinen [302]2 years ago

3 0

Answer:

25.2

Step-by-step explanation:

6/5 is 1.2, so it takes 1.2 minutes to run one lap.

This means 21 x 1.2 = the minutes it takes to run 21 laps around the track.

Therefore it takes 25.2 minutes to run around the track 21 times.

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Susan was given the following number to convert to scientific notation: 12,050,000 Her answer was 1.25 x 10^7 , but it was marke

KATRIN_1 [288]

Answer:

C. She left out a zero between the two and the five

Step-by-step explanation:

Given that Susan is expected to convert 12,050,000 to scientific notation, what Susan should have done is shown below:

Count the number of decimal places from your right up to before the first digit, and place the decimal point after the first digit. The number of decimal places counted would determine the exponent we are to use.

Here, we have 7 decimal places, counting from the right to the left, therefore, the exponent would be a positive 7.

What Susan should have is:

1.205 × 10⁷ NOT 1.25 × 10⁷.

1.25 × 10⁷ = 12,500,000, which is different from 12,050,000.

Her paper was marked wrong because: "she left out a zero between the two and the five"

7 0

2 years ago

The net of a square pyramid is shown below:

torisob [31]

28 is the correct answer.

7 0

2 years ago

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Translate this sentence into an equation. The difference of Mai's age and 12 is 60

daser333 [38]

Answer: 72

Step-by-step explanation:

7 0

2 years ago

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I just need no. a please help me to prove this.

OleMash [197]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π and cos A = cos B · cos C

scratchwork:

A + B + C = π

A = π - (B + C)

cos A = cos [π - (B + C)] Apply cos

= - cos (B + C) Simplify

= -(cos B · cos C - sin B · sin C) Sum Identity

= sin B · sin C - cos B · cos C Simplify

cos B · cos C = sin B · sin C - cos B · cos C Substitution

2cos B · cos C = sin B · sin C Addition

$2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}$ Division

2 = tan B · tan C

$\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}$

Proof LHS → RHS

Given: A + B + C = π

Subtraction: A = π - (B + C)

Apply tan: tan A = tan(π - (B + C))

Simplify: = - tan (B + C)

$\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)$

Substitution: = -(tan B + tan C)/(1 - 2)

Simplify: = -(tan B + tan C)/-1

= tan B + tan C

LHS = RHS: tan B + tan C = tan B + tan C $\checkmark$

5 0

2 years ago

Why is this not working -2^2

BARSIC [14]

Answer:

-4

Step-by-step explanation:

(-2)^2=4 because a negative number squared is always positive

-(2)^2=-4

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2 years ago

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