The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
Answer:
9(p + 4)
Step-by-step explanation:
One of the unknown variable is p.
First of all, we know that the number is 9 times as big (multiplication) as the new number obtained through the addition of four to p i.e (p + 4).
Translating the word problem into an algebraic expression, we have;
9 * (p + 4) = 9(p + 4)
Simplifying further, we have;
9p + 36
Answer:
Between 23.77% and 56.23%
Step-by-step explanation:
On your TI-84
Press STAT
Use right arrow to scroll over to highlight TESTS
Use down arrow to scroll down to A:1-PropZInt...
Press ENTER
Make the screen read
x:14
n:35
C-Level:0.95
Calculate
highlight Calculate
Press ENTER
See this:
(.2377,.5623)
p(hat)=.4
n=35
The confidence interval is 0.2377 < p < 0.5623
Between 23.77% and 56.23%
Convert the two fractions into simpler fractions: 3 2/5 --> 17/5 and 4 1/5 --> 21/5. Notice the the denominators are identical, so we simply add the numerators: (17 + 21)/5 = 38/5 = 7 3/5.
There is an easier way to do this, this is just the most clear way of seeing everything.
D. Multiplying 14.09 by 1000. It'll move the decimal point three places over. Making it 14090
