??? What is the rest of the question?
Answer:
y = 2x^2 is a parabola opening up with it's vertex at (0,0)... y=3x^2 -4 is also a parabola opening up, but it is 'thinner' in that it rises in y faster and it's vertex is at (0,-4)
Step-by-step explanation:
all equations of the type y = ax^2 + b are parabolas centered on the y-axis, soo the vertex is always on (0,b)
If a is positive then the parabola opens up,
the bigger a is, the 'thinner' the graph is, i.e. the faster the graph rises
the value of b determines the location of the vertex, if b is added, then the vertex rises over the x-axis, if b is subtracted then the vertex is below the x-axis
The location to the nonegative abscissa, positive ordinate is in the Q1 it means it is in the fisrt quadrant as seen in the next image: http://www.mathnstuff.com/math/spoken/here/1words/q/q2.htm
Hope this helps
Answer:
5 - 3
Step-by-step explanation:
easy way to find out
5-3= your answer in one step
