B squared - 4ac. A=-3 b=1 c= 3

Using the prostate data from the faraway package with lpsa (log prostate specific antigen) as response and lcavol (log cancer vo

rewona [7]

Answer:

Step-by-step explanation:

Given that,pros.

lpsa = 1.507 + 0.719 lcavol

lpsa=0.719 lcavol + 1.507

Comparing this to equation of a straight line, y=mx+c

Then,

slope (m) = 0.719

And intercept (c) on y axis is 1.507

Then, the x axis is lcavol

Also, the y axis is lpsa.

Then the linear model preview is

Check attachment for the preview.

8 0

3 years ago

Can someone help me with this math hw

AveGali [126]

Answer:

Step-by-step explanation:

F(x) = x² - 2x + 1

= (x - 1)²

By comparing this equation with the vertex form of the quadratic equation,

y = (x - h)² + k

Here, (h, k) is the vertex

Vertex of the parabola → (1, 0)

x-intercepts → (x - 1)² = 0

x = 1

y-intercepts → y = (0 - 1)²

y = 1

Now we can draw the graph of the given function,

From this graph,

As x → 0,

$\lim_{x \to 0^{-}} (x-1)^2=1$

$\lim_{x \to 0^{+}} (x-1)^2=1$

f(0) = (0 - 1)²

= 1

Since, $\lim_{x \to 0^{-}} (x-1)^2=\lim_{x \to 0^{+}} (x-1)^2=1$

Therefore, given function is continuous at x = 0.

8 0

2 years ago

Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre

gtnhenbr [62]

Answer: The meaning of each term of the Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = $3^1\times 1000$

After 2 hour, total number of amoebas = 3×3000= $3^2\times 100$

After 3 hour, total number of amoebas = 3×9000= $3^3\times 1000$

similarly, after h hours, total number of amoebas,

f(h) = $3^h\times 1000$

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = $(1+0.3)^1$

After 2 hour, total number of amoebas = $(1+0.3)^2$

After 3 hour, total number of amoebas = $(1+0.3)^3$

Similarly, after h hours, total number of amoebas,

f(h) = $(1+0.3)^h$

Where, 1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.

5 0

3 years ago

Read 2 more answers

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Naddik [55]

Answer:

C

Step-by-step explanation:

Since the graph hits 0 at x = 0, your y intercept is 0.

The graph is decreasing which means you have a negative slope.

They gave you a coordinate so use it to find the slope.

$\frac{1-0}{-3-0} = \frac{-1}{3}$

That's your slope.

C is the correct answer.

4 0

3 years ago

Read 2 more answers

HELP ASAP PLEASE

Roman55 [17]

Answer:

a. median is 8

b. first quartile is 7

c. third quartile is 9.5

d. below

e. below

Step-by-step explanation:

7, 10, 10, 6, 7, 8, 8, 7, 9.

Place number in order least to greatest

6, 7, 7, 7, 8, 8, 9, 10, 10

a. What is the median?

The median is the middle number in a data set

number of terms in data set (n) + 1 / 2 =

9 + 1 / 2 = 10 / 2

6, 7, 7, 7, 8, 8, 9, 10, 10

The median is 8

b. What is the first quartile?

Q1 is the central point between the smallest score and the median

6, 7, 7, 7

since there is even number of data points you find the average,

7 + 7 / 2 = 14 / 2 = 7

c. What is the third quartile?

Q3 is the central point between the median and the largest score

8, 9, 10, 10

since there is even number of data points you find the average,

9 + 10 / 2 = 19 / 2 = 9.5

d. Draw a box plot of the data.

below

e. Write two conclusions about the data shown in the box plot.

There are no outliers with a minimum of 6 and a maximum of 10. The Interquartile Range is 2.5 (9.5 - 7)

3 0

2 years ago