Answer:
6 6/7 km/h
Step-by-step explanation:
The relations between speed, time, and distance are ...
time = distance/speed
speed = distance/time
__
So, to find the average speed, we need to know the total distance and the total time. The distances are given, but we need to compute the times.
time jogging = (2 km)/(8 km/h) = 1/4 h
time walking = (2 km)/(6 km/h) = 1/3 h
Then the woman's average speed is ...
average speed = (total distance)/(total time) = (2 km + 2 km)/(1/4 h + 1/3 h)
= (4 km)/(7/12 h) = 48/7 km/h
= 6 6/7 km/h
Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
Answer:
3(4+x)
which can be simplified to 12+3x
Answer:
The distance, in feet, between the strip = 12 feet.
Step-by-step explanation:
From the figure attached in relation with the question, we can deduce that crosswalk is a parallelogram where
CD/AB = CE/AE
CD = 40
CE = 50
AE = 15
Let AB = x
50x = 15 × 40
X = 12
The distance, in feet, between the strip is therefore 12 feet
