Explain how you would find the sign of the quotient 32 divided by -2 divided by -16÷4

1 answer:

7 0

This may not be the best explanation but hopefully at the very least it'll guide you!
When you multiply or divide a negative by another negative, you get a positive. When it is a negative and a positive, it remains negative.
Assuming your question simplified into a equation (or number form? Been a while, haha!) is 32÷-2÷(-16÷4), it would end as a positive. Because you first divide the positive 32 by a negative 2, you get a negative. Because -16÷4 is in parenthesis, it is done because following the rest of the equation (P.E.M.D.A.S.!), it would be 32÷-2÷-4. Going from left to right, as you should, it results in a negative being divided by another negative, so you get a positive. 32÷-2÷(-16÷4) = 32÷-2÷-4 = -16÷-4 = 2!

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What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction.

Snowcat [4.5K]

You can simplify the given expression by taking out those factors who are perfect squares.

The simplified form of the given expression will be $\dfrac{\sqrt{3}}{2}$

<h3>How to simplify values which are under the root?</h3>

If possible, try to defactor what is inside the root.

For example, if 8 is under square root, then you can defactor 8 as made up of 2 times 2 times 2. Since 2 times 2 is perfect square, thus this can come out of the root.

Simply, some more such methods can be used to simplify these type of values.

<h3>Using the simplification method on given expression</h3>

$\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3\sqrt{2 \times 2 \times 2}}{4\sqrt{6}}\\\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3 \times 2\sqrt{2}}{4\sqrt{6}}\\

\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{6\sqrt{2}}{4\sqrt{6}} = \dfrac{\sqrt{6}\sqrt{2}}{4}\\\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{\sqrt{12}}{4} = \dfrac{\sqrt{4 \times 3}}{4} = \dfrac{\sqrt{3}}{2}$