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Musya8 [376]
3 years ago
9

A coin is tossed 13 times how many different outcomes are possible

Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0
Since the toss can either be heads or tails and only one of these can land at a time the answer is 13
Zielflug [23.3K]3 years ago
4 0
13 times because it has two sides...
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True or False: In order to prove that two functions are inverses, you can show that f (g(x)) = x AND show that g (f ()) = x. Thi
lbvjy [14]

Answer:

true

Step-by-step explanation:

trust me

6 0
3 years ago
An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest
nadya68 [22]
The equation for exponential decay is y=a*b^x, where <em>a</em> is the initial amount, <em>b</em> = 1 + <em>r</em> (the growth rate as a decimal number) and <em>x</em> is the number of time periods (in this case, minutes).  Substituting the information we have:
y=430(1+-0.274)^1^9&#10;\\=430(1-0.274)^1^9&#10;\\=430(0.726)^1^9=0.98.  To the nearest tenth of a gram, this would be 1.0 grams.
7 0
3 years ago
Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at
Oksanka [162]

a) The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively.

b) The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

P'(x,y) = k\cdot P(x,y) (1)

Where:

  • P(x,y) - Original point
  • P'(x,y) - Dilated point.

If we know that k = \frac{1}{3}, A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3), then the new points of the quadrilateral are:

A'(x,y) = \frac{1}{3}\cdot (0,6)

A'(x,y) = (0, 2)

B'(x,y) = \frac{1}{3} \cdot (-3,-6)

B'(x,y) = (-1, -2)

C'(x,y) = \frac{1}{3}\cdot (-9,-6)

C'(x,y) = \left(-3,-2\right)

D'(x,y) = \frac{1}{3}\cdot (-12,-3)

D'(x,y) = (-4, -1)

The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively. \blacksquare

b) A translation along a vector is defined by following operation:

P'(x,y) = P(x,y) +T(x,y) (2)

Where T(x,y) is the transformation vector.

If we know that T(x,y) = (-5,-1), A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3),

A'(x,y) = (0,6) + (-5, -1)

A'(x,y) = (-5, 5)

B'(x,y) = (-3, -6) + (-5, -1)

B'(x,y) = (-8,-7)

C'(x,y) = (-9, -6) + (-5, -1)

C'(x,y) = (-13, -7)

D'(x,y) = (-12,-3)+(-5,-1)

D'(x,y) = (-17, -4)

The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively. \blacksquare

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

7 0
2 years ago
A local pizzeria sold 65 pizzas yesterday. Suppose the actual number of pizzas sold today was 60. Describe
Rudik [331]
We need to find the difference first. 65 - 60 = 5. Now we must find what percent 5 is of 65. It is 7,7%. The number decreased, and so it is a 7,7% decrease.
7 0
3 years ago
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
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