Answer:
The actual distance between the cities is 211.67 cm.
Step-by-step explanation:
Given:
The map key indicates that 4.5 cm is equivalent to 75 cm.
Now, to find the actual distance between the cities if the cities are 12.7 cm apart on the map.
Let the actual distance be 
.
So, we set a proportion to find the actual distance:
4.5:12.7 = 75:x.
<em>Changing into fractions.</em>
<em>By cross multiplication we get:</em>
<em>Dividing both sides by 4.5 we get:</em>
Therefore, the actual distance between the cities is 211.67 cm.
Answer:
1 1/5 or 6/5
Step-by-step explanation:
So you get 2/5 every 1/2 hour so take the amount you have and times it by 3.
33 +4x = 513
4x = 480 (x = 480/4: x = 120)
Answer
Step 2 Divide each side by 4
Answer:
(x, y) = (1, -1)
Step-by-step explanation:
We'll write these equations in general form, then solve using the cross-multiplication method.
43x +67y +24 = 0
67x +43y -24 = 0
∆1 = (43)(43) -(67)(67) = -2640
∆2 = (67)(-24) -(43)(24) = -2640
∆3 = (24)(67) -(-24)(43) = 2640
These go into the relations ...
1/∆1 = x/∆2 = y/∆3
x = ∆2/∆1 = -2640/-2640 = 1
y = ∆3/∆1 = 2640/-2640 = -1
The solution is (x, y) = (1, -1).
_____
<em>Additional comment</em>
The cross multiplication method isn't taught everywhere. The attachment explains a bit about it. Our final relationship changes the order of the fractions to 1, x, y from x, y, 1. That way, we can use the equation coefficients in their original general-form order. (The fourth column in the 2×4 array of coefficients is a repeat of the first column.)
Answer:
, graph is there for reference.
Step-by-step explanation:
Given,
is the number of math problem Lucy solved.
is the number of pages she read.
She can do each math problem in 
minutes, therefore she can solve number of questions into 
minutes.
She can read each page in 
minutes, therefore she can read pages in 2.5y minutes.
As per given detail,
equation 1.
And,
It is given that number of math problems Lucy solved is 3 times the number of pages she read.
equation 2.
We need to find and intercept of each of the equation to graph them.
For 
put y=0
We will get 
Thus the point is 
Let us find 
by assuming 
we get 
Thus the point is 
Join these two points.
Similarly considering the other equation
Here x-intercept would be at 
We will get
Thus the point is 
Let us assume on more point, say 
, we get 
Thus the point is 
Join these two points.
We will get a point of intersection at 
Thus 
and 
