Question

12. F(x) = 4x squared

Answer 1

Answer:

y-intercept: $y=0$

axis of symmetry: $x=0$

vertex: $(0,0)$

Step-by-step explanation:

To find the y-intercept, set x = 0 and solve for y.

I am assuming f(x) = y

$y=4x^2$

$y=4(0)^2$

$y=0$

The y-intercept of the equation is y = 0.

Now, for the axis of symmetry, you need the equation $x=\frac{-b}{2a}$

In an equation.. $y=ax^2+bx+c$

In this case, there is only an a, so plug in the values into the equation.

$x=\frac{0}{2(4)}$

$x=0$

The axis of symmetry is x = 0.

To find the vertex, change the format of the equation from standard form to vertex form.

Vertex form: $y=a(x-h)^2+k$

The vertex is $(h,k)$

$y=4x^2 = 4(x+0)^2+0$

$(h,k)=(0,0)$

The vertex in this case is (0,0).

Graphing makes things a lot easier. If you can graph it, all you have to do is look at the graph and the answers are all there!

Hope this helped you!