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Tatiana [17]
3 years ago
9

How many 3s are in 2

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

two thirds of three thank you

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18, 7<br> The LCM of 18 and 7 is
Korvikt [17]

Answer:

126

Step-by-step explanation:

<em>Please</em><em> </em><em>mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>brainlist</em>

4 0
3 years ago
X − (y − y)= for x = 3 and y = 6
dusya [7]

Answer:

3

Step-by-step explanation:

x − (y − y)

3-(6-6)

3-0

3

3 0
3 years ago
Read 2 more answers
i am measurng two line segments the first line is 30centi meter long the second line segment is 500milli meter how long are the
Alexeev081 [22]

Answer    

Find out the how long are the two line segments together answer in cm .

To prove

As given

i am measurng two line segments the first line is 30centimeter long.

The second line segment is 500 millimeter .

As

1 millimeter = 0.1 centimeter

Now convert  500 millimeter into centimeter .

500 millimeter = 500 × 0.1 centimeter

                         = 50 centimeter

Thus second line segment be  50 centimeter long .

Total length of  two line segments = 30 + 50

                                                        = 80 cm

Therefore the 80 cm long are the two line segments together answer in cm .




8 0
3 years ago
A 20 foot ladder is leaning against the side of a building. The bottom of the ladder is 4 feet from the wall. How many feet abov
Semenov [28]
It form a right triangle
legnth of ladder is hypotonuse
bottom of ladder from wall distance is one leg
distance up wall is other leg
a^2+b^2=c^2
c=hypotonuse and a and b are legs

4^2+b^2=20^2
16+b^2=400
minus 16 both sides
b^2=384
sqrt both sides
b=8√6 ft
aprox
b=19.59ft from ground
6 0
3 years ago
A club raises $3,207 to buy stuffed animals for a local children's hospital. Each stuffed animal costs $17. What is the maximum
Ksju [112]

Answering:

188

Explaining:

To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.

After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.

Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.

Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.

4 0
3 years ago
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