Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
per Bowl XLVIII (the same players from the preceding exercise). Are the measures of variation likely to be typical of all NFL players? 1. 1892. 2543. 2354. 2255. 1906. 3057. 1958. 2029. 19010. 25211. 305
1 answer:
Answer:
No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.
Step-by-step explanation:
1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.
The Range Δ is calculated:
Maximum value - Minimum value for weight
Mean:
Variance:
The Standard Deviation of the sample
2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),
Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.
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Answer:
Step-by-step explanation:
1. Make sure all your denominators are the same, you can do this by multiplying them all by 3 or 7, 2 and 1/3 would become 2 7/21, 3/7 would become 9/21, 2 and 1/3, would become 2 and 7/21, and so on and so forth, leaving us with
2+
/ 2
* 1
2. Now, I would go and solve each side of the equation because we divide them, we can add 2 and
together to get 2
, because 7 + 9 = 16
2 / 2
* 1
3. We can do the same thing to the other side, by multiplying the two of them. I'm going to convert both of them to just fractions, 2 becomes
and 1
becomes
*
Now we can reduce them, and for our first fraction divide the top and bottom by 7, giving us and the second one by 3, which gives us
*
now we cross divide, where we replace the 7's with ones because they're right across from each other to get
and
, or just 10.
* 10 =
4. So now we can do a similar thing with the first half of our equation and convert it into a fraction and not a mixed number.
/
Now we multiply divide them, and the easiest way I learned how to do this was by keep the first fraction in its place, and flipping the denominator and numerator of the second, and multiplying them.
so *
which if we multiply both sides, you get
I'll save you some times and simplify it for you, the greatest common factor is 6 so we divide the top and bottom by 6 to get