solve for "k", to find k or the "constant of variation"
then plug k's value back to
now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
Charlene's long distance telephone service charges $7.50 per month plus $0.12 for each minute. Her bill last month was $13.02. W
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solve for "k", to find k or the "constant of variation"
then plug k's value back to
now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is