Karen is seven years older than suzanne.Four years ago,karen was twice as old as suzanne was.How are they now?
1 answer:
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Answer:
- distance traveled: 30 m
- displacement: 21.4 m
Step-by-step explanation:
You want the distance traveled and the displacement after walking 17 m south and 13 m east.
<h3>Distance</h3>The distance traveled is the sum of the lengths of each leg of the trip:
17 m + 13 m = 30 m
You have traveled a distance of 30 m.
<h3>Displacement</h3>The displacement is the distance from your final position to your starting position. If you draw a diagram of the journey, you see the displacement is the hypotenuse of a right triangle with legs 17 m and 13 m. The Pythagorean theorem can help you find this length:
h = √(a² +b²)
h = √(17² +13²) = √(289 +169) = √458 ≈ 21.401
At the end of your walking, you are 21.4 m from where you started.
Answer:
A straight line of approximately 75 meters, 1.4º north
Step-by-step explanation:
Hi, let's make it step by step to make it clearer
1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in . To say 30º Northeast is 30º clockwise (or 60º counter clockwise).
2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.
3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.
So, let's calculate the norm which is the length of the each vector.
1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.
Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:
Now, let's calculate each vector length by calculating the norm.
The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.
