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elena55 [62]
3 years ago
5

Real Answers Only!!!!

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

The correct answer is C) Reflection across the Y-axis.

Step-by-step explanation:

This is because only the x-coordinates changed. If these coordinates were reflected across both the x and y axis' the sign of both the x and y coordinates would have changed. When  you reflect a point across the x axis, the y-coordinates change their sign. When you <u><em>reflect </em></u><u>a point across the y axis</u>, the <u>x-coordinates change</u> their sign.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

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Please help me out!
ludmilkaskok [199]

Answer:

it is the there'd one

if this is wrong sorry

3 0
2 years ago
There are 65 campers at fun camp. only 53 campers brought sleeping bags. how many campers did not bring sleeping bags?
elena-s [515]
So you have to just subtract, 65-53=12 that didn't bring sleeping bags
8 0
3 years ago
Write a quadratic equation having the given solutions. 10,2
n200080 [17]

(x-10)(x-2)=0
x(x-2) -10(x-2)=0
x^2 -2x -10x -20 =0
x^2 -12x -20= 0
7 0
4 years ago
5/11 times -8 I need this plzzzzzzzzzzzzzzzzz
Pavel [41]
5/11 times -8

5/11 × -8/1

-8*5 = -40

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Hope this helps
4 0
3 years ago
Read 2 more answers
A recent survey of students at John Tukey High School revealed that
RoseWind [281]

Answer:

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor, or they are not. Students are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

18% of the students are in favor of changing the dress code.

This means that p = 0.18

You randomly select 15 students

This means that n = 15

What is the probability that at least three of these students are in favor of the proposal to change the dress code?

This is

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.18)^{0}.(0.82)^{15} = 0.051

P(X = 1) = C_{15,1}.(0.18)^{1}.(0.82)^{14} = 0.1678

P(X = 2) = C_{15,2}.(0.18)^{2}.(0.82)^{13} = 0.2578

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.051 + 0.1678 + 0.2578 = 0.4766

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.4766 = 0.5234

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

8 0
3 years ago
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