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Nostrana [21]
4 years ago
6

In 2012, Germans paid 1.65 Euros per liter of gasoline. At the same time, American prices were $3.90 per gallon. a. How much wou

ld one gallon of European gas have cost in dollars? b. How much would one liter of American gasoline have cost in Euros? (One US dollar = 0.76 Euros, 1 gallon = 4.55 liters)
Physics
1 answer:
alex41 [277]4 years ago
8 0

Germans paid 1.65 euros per liter of gasoline

American prices were $3.90 per gallon and for one liter = $3.90 / 4.55 = $0.86

One US dollar = 0.76 Euros

If Germans paid 1.65 euros for 1 liter, they will pay for 1 gallon = 1.65 euros x 4.55 liters = 7.51

Price of one gallon Germans paid in euros = 7.51 euros

As, 1 Us dollar=0.76 euros from this we get 1 euro = 1.31 dollars

So, price of one gallon Germans paid in dollars = 7.51 x 1.31 = $9.84

American gasoline have cost in euros per liter = 0.86 x 0.76 = 0.65 euros

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Answer:

The potential for r > rb is equal to zero.

Explanation:

For r > rb, the potential is:

V=\frac{Kq}{r}

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V_{(r)} =\frac{K(+\epsilon )}{r} +\frac{K(-\epsilon )}{r}

K=\frac{1}{4\pi \epsilon _{o}  }

V_{(r)} =\frac{K(+\epsilon )}{r} -\frac{K(\epsilon )}{r}\\V_{(r)}=0

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4 years ago
A football punter accelerates a football from rest to a speed of 15 m/s during the time in which his toe is in contact with the
KengaRu [80]
Use F=ma formula
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4 years ago
In the data table , distance is measured in meters and time is in seconds. Calculate the mans average velocity using the equatio
Artist 52 [7]

Answer:

3.626 m/s

Explanation:

v=d/t

1. -0.02/0 = 0 m/s

2. 0.86/0.2 = 4.3 m/s

3. 1.71/0.4 = 4.275 m/s

4. 2.54/0.6 = 4.23 m/s

5. 3.32/0.8 = 4.15 m/s

6. 4.08/1.0 = 4.08 m/s

7. 4.79/1.2 = 3.99 m/s

8. 5.48/1.4 = 3.91 m/s

9. 6.15/1.6 = 3.84 m/s

10. 6.76/1.8 = 3.76 m/s

11. 7.37/2.0 = 3.66 m/s

12. 7.92/2.2 = 3.6 m/s

13. 8.45/2.4 = 3.52 m/s

14. 8.96/2.6 = 3.45 m/s

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3 years ago
A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits
Westkost [7]

Answer:

(a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Explanation:

Given that,

Mass of neutron M_{n}= 13M_{s}

Density of neutron \rho=4.8\times10^{17}\ kg/m^3

(a). We need to calculate the rotational inertia

Using formula of rotational inertia  for sphere

I=\dfrac{2}{5}MR^2...(I)

We know that,

\rho=\dfrac{M}{V}

Put the value of volume

\rho=\dfrac{3M_{n}}{4\pi R^3}

R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value of R in equation (I)

I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value into the formula

I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}

I=5.72\times10^{39}\ kg m^2

The rotational inertia is 5.72\times10^{39}\ kg m^2.

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

\tau=I\times \alpha

Put the value into the formula

\tau=5.72\times10^{39}\times5.6\times10^{-5}

\tau=3.20\times10^{35}\ N-m

The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Hence, (a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

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