Answer:
The hydro static force on the back of the dam is 
Explanation:
Given that,
Width b= 1000 m
Depth d= 200 m
We need to calculate the average pressure
Using formula of average pressure
Put the value into the formula
We need to calculate the hydro static force on the back of the dam
Using formula of force
Put the value into the formula
Hence, The hydro static force on the back of the dam is
Answer:
The avarage power of the body is 96.898 watts.
Explanation:
We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that 
and 
, the power of body, measured in watts, is:
The avarage power of the body is 96.898 watts.
Answer:
660V
Explanation:
V=IR
V=11×60
=660V
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<span>17%
Any object that is floating will display the volume of fluid that matches the mass of the object that's floating. So if the object is 100% as dense as the fluid, it will just barely sink, if it's 50% as dense as the fluid, 50% will be submerged, etc. So let's see what percent of mercury's density is concrete.
2.3x10^3 / 13.6x10^3 = 0.169117647 = 16.9117647%
Rounding to 2 significant figures gives 17%.
So 17% of a piece of concrete will be submerged in mercury when it's floating in mercury.</span>
Answer:
<h2>0.245cm/min</h2>
Explanation:
The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.
Using chain rule to express dV/dt;
dV/dt = dV/dr*dr/dt
dr/dt is the rate at which the radius of the gallon is increasing.
From the formula, dV/dr = 3(4/3πr^3-1))
dV/dr = 4πr²
dV/dt = 4πr² *dr/dt
500 = 4πr² *dr/dt
If radius r = 40;
500 = 4π(40)² *dr/dt
500 = 6400π*dr/dt
dr/dt = 500/6400π
dr/dt = 5/64π
dr/dt = 0.245cm/min
Hence, the radius of the balloon is increasing at the rate of 0.245cm/min
