Answer:
The pressure of the remaining gas in the tank is 6.4 atm.
Explanation:
Given that,
Temperature T = 13+273=286 K
Pressure = 10.0 atm
We need to calculate the pressure of the remaining gas
Using equation of ideal gas

For a gas

Where, P = pressure
V = volume
T = temperature
Put the value in the equation
....(I)
When the temperature of the gas is increased
Then,
....(II)
Divided equation (I) by equation (II)





Hence, The pressure of the remaining gas in the tank is 6.4 atm.
Answer:
jwuwhisbuebeu said that good morning and private s the
<h2>
All waves must ____ have to travel through
</h2>
Explanation:
Wave
It is the periodic disturbance in a medium.
Types of Wave
There are two types of wave in general depending upon their propagation through a substance.
• Mechanical
• Electromagnetic
Mechanical Wave
It is the kind of wave which needs medium to travel. For example: Sound Wave
That means sound can be heard only whenever there is presence of certain substance like water, glass, air etc .It can’t be heard in vacuum no matter how loud is the sound.
Electromagnetic Wave
Is that which can travel through medium as well as through vacuum. For example: Light
But unlike sound, light can be seen through a substance or in vacuum. That is the reason it is referred as electromagnetic wave.
Answer:


Explanation:
Since we have given values of ω₀=32.o rad/s ,ω=0 and α=-0.700 rad/s² to find t we use below equation

To find revolutions we use below equation

Substitute the given values to find revolutions α
So

To convert rad to rev:

Answer:
The value is 
Explanation:
From the question we are told that
The initial speed of the roller coaster is 
The length of the hill is 
The acceleration of the roller coaster is 
Generally the acceleration is mathematically represented as

Here
is the initial time which is equal to zero
is the final velocity which is mathematically represented as

So




Solving this using quadratic formula we obtain


Generally time cannot be negative so

Generally the final velocity is mathematically represented as

