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liraira [26]
3 years ago
15

A 2 kg blob of putty moving at 3 m/s slams into a 3 kg blob of putty at rest. Which blob has the most momentum prior to the coll

ision?
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

initial momentum of 2 kg blob is given as

P_1 = m_1v_1

here we have

m_1 = 2kg

v_1 = 3m/s

P_1 = 3(2) = 6 kg m/s

initial momentum of 3 kg blob is given as

P_2 = m_2v_2

here we have

m_2 = 3kg

v_2 = 0m/s

P_2 = 3(0) = 0 kg m/s

So initially 2 kg Blob has most momentum before they collide

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Passengers in an aircraft are subject to the Normal and Gravity Force acting on them at a low 'orbit', so tiny that it can be many times compared to the same surface of the earth when speaking in general terms.

In a high orbit space vehicle or in the same space, said force decreases considerably or simply disappears, generating the sensation of weightlessness.

Remember that the Force of Gravity is given under the principle

F_g = \frac{GMm}{r^2}

Where,

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3 years ago
What type of heat transfer is used in a restaurant that uses ovens with fans inside?
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convection


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5 0
3 years ago
Give an example of a Claim.
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5 0
3 years ago
(I) In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second pro
Kipish [7]

Answer:

The second projectile was 1.41 times faster than the first.

Explanation:

In the ballistic pendulum experiment, the speed (v) of the projectile is given by:  

v = \frac{m + M}{m} \cdot \sqrt{2gh}

<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum.   </em>

To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:    

\frac{v_{2}}{v_{1}} = \frac{\frac{m_{2} + M}{m_{2}} \cdot \sqrt{2gh_{2}}}{\frac{m_{1} + M}{m_{1}} \cdot \sqrt{2gh_{1}}}           (1)

<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively.  </em>

Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):

\frac{v_{2}}{v_{1}} = \frac{\sqrt{h_{2}}}{\sqrt{h_{1}}}  

\frac{v_{2}}{v_{1}} = \frac{\sqrt{5.2 cm}}{\sqrt{2.6 cm}}

\frac{v_{2}}{v_{1}} = 1.41  

Therefore, the second projectile was 1.41 times faster than the first.  

I hope it helps you!

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3 years ago
To get maximum current in a circuit, the resistance should be in _____
Tanzania [10]

Answer:

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