Answer:
Step-by-step explanation:
V of a cube is s^3
V = 512
s = cube root of (V)
s = cube root of 512 cm^3
s = 8
The area of one face of the cube is s^2
s = 8
Area 1 face = 8^2
Area of 1 face = 64 cm^2
In this case, to flip any of the points to map
up accurately to the other points, we would have to do a transformation of reflection
about the y-axis. The reason behind this is that out of other transformation
process, we can only achieve the image of triangle ∆A’B’C’ through reflection.
Dilation will not work since it only changes
the size of the object. The shape and position will not affected.
A translation will not work because although
the shape can move, it still needs to flip to achieve triangle ∆A’B’C’.
A rotation will also not work because when you
rotate it, the shape will still not map over the new one.
<span>
<span>Therefore the only answer to this question would be to
reflect triangle ∆ABC about the y-axis.</span></span>
Perimeter = add all the sides
Pool has 4 sides
So
22.3 + 22.3 = 44.6
75+75 = 150
150 + 44.6 = 194.6ft
A) The intersection occurs at the same height 'y', so the y of each equation must be equal:
y=y implies <span>2−x = 8x+4. The solution is -2=9x, x = -2/9=2/3, and y = 20/9
(-2/9,20/9)
</span>
B)
X | Y1 | Y2
_____________
-3 5 -20
-2 4 -12
-1 3 -4
0 2 4
1 1 12
2 0 20
3 -1 28
C) I would draw each line with the values on the table. Where both lines cross is the intersection point. It should be (-2/9, 20/9)
