All categories

2 years ago

Number 8 please thanks!

Mathematics

1 answer:

WINSTONCH [101]2 years ago

4 0

$4b(b+2)=16+4b^2\\4b^2+8b=16+4b^2\\8b = 16 + 4b^2-4b^2\\8b = 16\\b = 2$

Hope that helps!

You might be interested in

Julie buys a pair of earrings for $7. Now she would like to the same earrings for 2 friends. How much will she spend for all 3 p

ankoles [38]

The easiest way to do this is to multiple 7 and 3, which gives you 21. Julie will spend $21 on the gifts.

5 0

2 years ago

Read 2 more answers

Describe the relationship between the terms in each arithmetic sequence. Then

shtirl [24]

Answer:

(a) The sum of the previous term and 9

(b) 36, 45, 54

Step-by-step explanation:

Given

Sequence: Arithmetic Progression

$0,9,18,27$

Solving (a): Describe the relationship in each term

First, we calculate the common difference (d)

In arithmetic progression:

$d = T_n - T_{n-1}$

Take n as 2

$d = T_2 - T_{2-1}$

$d = T_2 - T_{1}$

Where

$T_2 = 9\ and\ T_1 = 0$

$d =9-0$

$d =9$

<em>The relationship is: The sum of the previous term and 9</em>

Solving (b): The next three terms

As said in (a) each term is derived from a sum of 9 and the previous term

So, we have:

$Next\ Term = 27 + 9 = 36$

$Next = 36 + 9 = 45$

$Next = 45 + 9 = 54$

Hence, the next three terms are: 36, 45 and 54

4 0

2 years ago

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

3 years ago

Please Help! 40 Points!

belka [17]

Fyi I didn't find this on google or anything I did the calculation on my computer and yes this is correct...

If it's wrong I'm sorry...

3 0

2 years ago

A recursive rule for a geometric sequence is a1=49;an=3an−1.

dalvyx [7]

I think it should be an= 49x3^(n-1)

3 0

2 years ago