What is the reason for 2 and 4

Locating Zeros of Polynomial Function: Approximate the real zeros to the nearest tenth

solmaris [256]

we are given

$f(x)=2x^4-x^3+x-2$

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

$f(-2)=2(-2)^4-(-2)^3+(-2)-2$

$f(-2)=36$

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

so, this is FALSE

5 0

4 years ago

Which of the following theorems verified that angle xyz is congruent too angle uwv?

icang [17]

Answer:

Option B. AA

Step-by-step explanation:

we know that

Angle-Angle (AA) Similarity Postulate, states that If two angles of one triangle are congruent to two angles of another, then the triangles must be similar

In this problem

In the triangle XYZ

∠X=70°

∠Y=90°

∠Z=90°-70°=20° (remember that angle X and angle Z are complementary)

In the triangle UWV

∠V=20°

∠W=90°

∠U=90°-20°=70° (remember that angle V and angle U are complementary)

therefore

Traingles XYZ and UWV are similar by AA Similarity Postulate

3 0

3 years ago

Evaluate 11+(−7)2−911+(−7)2−9.

Tomtit [17]

$13( - 7) - 913( - 7) - 9 \\ 4(49) - 913 \\ 196 - 913 = - 717$

6 0

3 years ago

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 20

Murljashka [212]

Answer:

There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1432

p = 23% = 0.23

Alpha, α = 0.05

Number of theft complaints , x = 321

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.23\\H_A: p < 0.23$

This is a one-tailed test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{321}{1432} =0.2241$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2241-0.23}{\sqrt{\frac{0.23(1-0.23)}{1432}}} = -0.5305$

Now, we calculate the p-value from the table.

P-value = 0.298

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Conclusion:

Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

5 0

3 years ago

Find the equation of the circle that is shifted 5 units to the left and 2 units down from the circle with the equation x^2+y^2=1

marysya [2.9K]

Shifting a circle results to changes in the coordinates of the circle. For instance, if the coordinates of the center of the circle is taken to be (0,0), the new coordinates will be [(0+5),(0+2)] after shifting. The equation of the circle will also change with the same margin.

That is, the new equation will be;
(5+x)^2+(2+y)^2 =19

Notice, only the coordinates changes.

6 0

3 years ago