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3 years ago

PLSS HELP

Mathematics

2 answers:

dsp733 years ago

4 0

Answer:

B,C, and D

Give thanks and brainliest!! :P

Aneli [31]3 years ago

4 0

Answer: The correct answer is C. Because, when two figures are congruent all their measurements are the same.

Step-by-step explanation:

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HELPPPPPPP ITS FOR MY STUDY GUIDE

RoseWind [281]

Answer:The answer is A If you wanna make sure just search up those coordinates and it should be right

Step-by-step explanation:

7 0

3 years ago

Lmk ASAP please you’re the

tamaranim1 [39]

9514 1404 393

Answer:

a ≈ 4.68

Step-by-step explanation:

The law of cosines tells you ...

a² = b² +c² -2bc·cos(A)

a = √(b² +c² -2bc·cos(A))

a = √(5² +8² -2·5·8·cos(33°)) = √(25 +64 -80·0.83867) ≈ √21.906

a ≈ 4.68

6 0

3 years ago

Read 2 more answers

Need pre-cal help. Will mark best answer brainliest

OlgaM077 [116]

so, let's keep in mind that

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}$

so let's make a quick table of those solutions, say A, B, C solutions with x,y,z liters of acid, with an acidity of 0.25, 0.40 and 0.60 respectively.

$\bf \begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ A&x&0.25&0.25x\\ B&y&0.40&0.4y\\ C&z&0.60&0.6z\\ \cline{2-4}&\\ mixture&78&0.45&35.1 \end{array} \\\\\\ \begin{cases} x+y+z=78\\ 0.25x+0.4y+0.6z=35.1 \end{cases}$

we know she's using "z" liters and those are 3 times as much as "y" liters, so z = 3y.

$\bf \begin{cases} x+y+3y=78\\ x+4y=78\\[-0.5em] \hrulefill\\ 0.25x+0.4y+0.6(3y)=35.1\\ 0.25x+0.4y=1.8y=35.1\\ 0.25x+2.2y=35.1 \end{cases}\implies \begin{cases} x+4y=78\\\\ 0.25x+2.2y=35.1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x+4y=78\implies \boxed{x}=78-4y \\\\\\ \stackrel{\textit{using substitution on the 2nd equation}}{0.25\left( \boxed{78-4y} \right)+2.2y=35.1}\implies 19.5-y+2.2y=35.1$

$\bf 1.2y=15.6\implies y=\cfrac{15.6}{1.2}\implies \blacktriangleright y=13 \blacktriangleleft \\\\\\ x=78-4y\implies x=78-4(13)\implies \blacktriangleright x=26 \blacktriangleleft \\\\\\ z=3y\implies z=3(13)\implies \blacktriangleright z=39 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{25\%}{26}\qquad \stackrel{40\%}{13}\qquad \stackrel{60\%}{39}~\hfill$

5 0

3 years ago

You begin solving the equation 3+4x=51 by subtracting 3 from both sides. Which is the best choice for Step 2? Subtract 48 from b

Angelina_Jolie [31]

You will divide both sides by 4.

3 0

3 years ago

Read 2 more answers

Maria walked 3 km west and 4 km south calculate how far she is from her starting point.

Rufina [12.5K]

Answer:

5 km

Step-by-step explanation:

We are given the distances walked by Maria;

3 km west and 4 km south

We are required to determine the displacement from her starting point;

We are going to use Pythagoras's theorem;

a² + b² = c²

Taking, the distances towards south and towards west as the legs of the triangle;

Then, c² = 3² + 4²

= 25

c = √25

= 5 km

Therefore, the displacement from the starting point is 5 km

8 0

3 years ago