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Iteru [2.4K]
4 years ago
11

Factor the following polynomial 14c^2+15c

Mathematics
2 answers:
Likurg_2 [28]4 years ago
6 0

Answer:

c ( 1 4 c + 1 5 )

Step-by-step explanation:

1 4 c ² + 1 5 c

Factor out c

c ( 1 4 c + 1 5 )

sergeinik [125]4 years ago
4 0

Answer:

 c • (15c2 + 14)

Step-by-step explanation:

14c +  (3•5c3)

3.1     Pull out like factors :

  15c3 + 14c  =   c • (15c2 + 14)

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6- 3/4x + 1/3 = 1/2 x + 5​
Wittaler [7]

Answer: Solve for

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x

by simplifying both sides of the equation, then isolating the variable.

Exact Form:

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16

15

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16

15

Decimal Form:

x

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1.0

¯

6

x

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Mixed Number Form:

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1

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An approximate solution to an equation is found using this iterative process
garik1379 [7]

Answer:

a)(i)x2= -0.5

b)(ii)x3= -0.28125

Step-by-step explanation:

Sorry But I cannot explain the working out.

8 0
3 years ago
What is the line segment of AB?
malfutka [58]
I'm going with 10. Let me know.
7 0
4 years ago
Read 2 more answers
A friend tells you that he has a cubic equation with exactly three complex roots. Determine which explanation best explains why
Ksju [112]
Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.

a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.

therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.

if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
3 0
3 years ago
Read 2 more answers
Select all the pairs of equivalent expressions.
iren2701 [21]

Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

3 0
4 years ago
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