Answer:
x= 5 , for c to be same on each eqn
If i did the math correctly one number is 50
19 has two factors: 1, 19
21 has four factors: 1, 3, 7, 21
23 has two factors: 1, 23
And we need a number that has more than four factors and is greater than 25.
Factors of 50- 1, 2, 5, 10, 25, 50
50has six factors and is greater than 25.
Answer:
444 adult ticket
763 student ticket
Step-by-step explanation:
let a = number of adult ticket
let s = number of student ticket
s+a=1207
5a+s=2983
get s by itself in the 1st equation so you can plug it into the 2nd
s+a=1207
-a -a
s=1207-a
5a+(1207-a)=2983
solve for a
4a+1207=2983
-1207 -1207
4a= 1776
444
this is adult ticket amount
subtract this from 1207 to get student amount
1207-444=763
