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Mila [183]
3 years ago
10

What is the product?(4x)(-3x^8)(-7^3)

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

4116x^9

Step-by-step explanation:

(4x)(-3x^8)(-7^3)

(-12x^9)(-343)

4116x^9

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Jim wishes to buy 3 gifts that cost 15 dollars, 9 dollars, and 12 dollars. he has 1/4 of the money he needs, how much more money
Archy [21]
In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
7 0
3 years ago
Line AB contains points A(4, 5) and B(9, 7). What is the slope AB
MatroZZZ [7]
For the answer to the question, what is the slope AB if l<span>ine AB contains points A(4, 5) and B(9, 7)?
The</span> answer <span>to </span>this question is 2/5.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
4 0
2 years ago
Read 2 more answers
315,728 rouned to the nearest ten thousand
Masja [62]

Answer:

320,000 is the answer

Step-by-step explanation:

have a good day!!

8 0
2 years ago
What are the solutions to the inequality (x-3)(x+5) SO?
nikitadnepr [17]

Answer:

x

2

+

2

x

−

15

Step-by-step explanation:

3 0
3 years ago
Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
3 years ago
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