Question

Find the probability that the hitter makes 10 outs in 10 consecutive​ at-bats, assuming​ at-bats are independent events.​ Hint: The hitter makes an out
72
72​% of the time.

​P(hitter makes 10 consecutive ​outs)
equals

Answer 1

Answer:

0.037

Step-by-step explanation:

If the hitter makes an out 72​% of the time, then the probabilty that he makes hit in 1 at-bat is $p=0.72$ and the probabilty that he doesn't make hit in 1 at-bat is $q=1-p=1-0.72=0.28.$

The probability that the hitter makes 10 outs in 10 consecutive​ at-bats, assuming​ at-bats are independent events is

$P=p^{10}=(0.72)^{10}\approx 0.037.$