Answer:
The point at which the banner should be attached to the archway is going to be given by the point(s) at which the two equations intercept:
y = -x^2 + 6x and 4y = 21 − x
Solving the system of equations, we find that they intercept at: (1, 5) and (5.25, 3.938)
Therefore, the banner should be attached to the archway at the points (1, 5) and (5.25, 3.938)
see explanation
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
A (- 1, - 5 ) → A' (- 1, 5 )
B (2, - 3 ) → B' (2, 3 )
C (3, - 5 ) → C' (3, 5 )
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
A' (- 1, 5 ) → A'' (1, 5 )
B' (2, 3 ) → B'' (- 2, 3 )
C' (3, 5 ) → C'' ( - 3, 5 )
x = -13/5
let x be the number
8x + 6 = 3x - 7
move variables to left and numbers to right
8x - 3x = - 7 -6
5x = -13
Step-by-step explan
58cm
15+14+5+8+6=48
missing side = 15-5 =10
48+10=58
See below
linear equation: y=2x+10
x=cost per movie rented
10=$10 for the membership
24=2x+10 (24 being total you want to spend)
subtract 10 from each side
14=2x
divide by 2
7=x
He can rent no more than 7 movies if he want to spend $24 or less in the month