The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 + 6x. The university is hanging a
banner at the main entrance at an angle defined by the equation 4y = 21 − x. At what points should the banner be attached to the archway?
1 answer:
Answer:
The point at which the banner should be attached to the archway is going to be given by the point(s) at which the two equations intercept:
y = -x^2 + 6x and 4y = 21 − x
Solving the system of equations, we find that they intercept at: (1, 5) and (5.25, 3.938)
Therefore, the banner should be attached to the archway at the points (1, 5) and (5.25, 3.938)
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The solutions for the quadratic equation are given as follows:
x = -1, x = 7/5
<h3>What is a quadratic function?</h3>A quadratic function is given according to the following rule:
y = ax^2 + bx + c
The solutions are:
In which:
For this problem, the equation is:
5x² - 2x - 7 = 0.
Hence the coefficients are a = 5, b = -2 and c = -7, and then the solutions are found as follows:
The solutions are:
x = -1, x = 7/5
More can be learned about quadratic equations at brainly.com/question/24737967
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Answer:
x < 6
Step-by-step explanation:
Subtract 4 form both sides
Multiply both sides by 3