The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 + 6x. The university is hanging a
banner at the main entrance at an angle defined by the equation 4y = 21 − x. At what points should the banner be attached to the archway?
1 answer:
Answer:
The point at which the banner should be attached to the archway is going to be given by the point(s) at which the two equations intercept:
y = -x^2 + 6x and 4y = 21 − x
Solving the system of equations, we find that they intercept at: (1, 5) and (5.25, 3.938)
Therefore, the banner should be attached to the archway at the points (1, 5) and (5.25, 3.938)
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root
Step-by-step explanation:
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Answer:
here question was not clear
Answer: 429.88
Step-by-step explanation:
The first 40 hours is at 9.50
40 *9.50 =380
The remaining hours is at 9.50 * 1.5 or 14.25
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Add together
380+49.88 =429.88
3/4+5/6 divided by 2/3 is 8/4 or 2
Do 5/6 divided by 2/3 first to get 5/4
then use 5/4 to +3/4 and the answer is 8/4 or 2
Answer:
14 students
Step-by-step explanation:
Given
Let:
read a book
watched TV
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-- total



Required
Students that did both (x)
This is calculated using:

So, we have:

This gives:

Open brackets


Collect like terms


<em>Hence, 14 students did both</em>