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3 years ago

7

Circular gears P and Q start rotating at the same time at constant speeds. Gear P makes 10 revolutions per minute and Gear Q mak

es 40 revolutions per minute. How many seconds after the gears start rotating will gear Q have made exactly 6 more revolutions than gear P ?
A. 6
B. 8
C. 10
D. 12
E. 15

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

12 minutes

Option D

Step-by-step explanation:

Given that circuar gears P and Q start rotating at the same time at constant speeds.

Gear P makes 10 revolutions per minute and Gear Q makes 40 revolutions per minute.

Both gears start at the same time.

No of rotations per minute are 10 and 40

Difference is 30 in one minute

For 6 difference we must have exactly 1/5 minutes

which equals 12 seconds.

In 1/5 minutes or 12 seconds gear P would have completed 2 revolutions while Gear Q would have completed 8 revolutions thus making difference as 6.

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100

Step-by-step explanation:

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3 years ago

PLEASE HELP 2 QUESTIONS 45 POINTS!!!!!!!!!

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Answer:

1. -8x² - 16x - 6 a = -8, b = -16, c = -6

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Step-by-step explanation:

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2 years ago

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

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$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

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The above computations show that opposite sides are parallel, because they have equal slope

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brainly.com/question/3050890

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2 years ago

A line passes through (-2, -3) and (4, -6) what is the slope of the line ?

MrRissso [65]

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3 years ago

Read 2 more answers

Which systems of equations intersect at point A in this graph?

abruzzese [7]

Answer:

The point of intersection of the system of equations is:

(x, y) = (-2, 1)

The correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

Step-by-step explanation:

Given the point

A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Arrange equation variable for elimination

$\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}$

so

$y+3x=-5$

$-$

$\underline{y-4x=9}$

$7x=-14$

so the system of equations becomes

$\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}$

Solve 7x = -14 for x

$7x=-14$

Divide both sides by 7

$\frac{7x}{7}=\frac{-14}{7}$

Simplify

$x = -2$

For y - 4x = 9 plug in x = 2

$y-4\left(-2\right)=9$

$y+4\cdot \:2=9$

$y+8=9$

Subtract 8 from both sides

$y+8-8=9-8$

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) = (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

3 0

3 years ago