Answer:
776644 rounds to 777000
Step-by-step explanation:
hundred thousand ten thousand thousand hundred tens ones
7 7 6 6 4 4
We are rounding to the nearest thousand so we are rounding the first 6. We need to look at the next 6 (the one in the hundreds place) 6>=5 so we will round the 6 in the thousands place up to 7
776644 rounds to 777000
Answer:
it would be 103/25
Step-by-step explanation:
Answer: The probability that the fruit is an orange or a pear is 
.
Step-by-step explanation:
Given : Emily has 12 fruits in her bowl.
She has 3 apples, 5 bananas, 1 pear and 3 oranges.
A fruit is selected at random.
P(orange) = 
P(pear)= 
Since both events of selecting orange and pear are mutually exclusive , so
The probability that the fruit is an orange or a pear = P(orange) + P(pear)
Therefore , the probability that the fruit is an orange or a pear is .
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
(6×30)×3 is the answer to this equation please reward brainlest
