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3 years ago

a pair of dice is rolled, what is the probability that the sum is less than 6, given that the sum is 4?

Mathematics

2 answers:

solong [7]3 years ago

6 0

Answer:

1/6

Step-by-step explanation:

there are 6 possibilities and you can only get 1 number

vladimir1956 [14]3 years ago

5 0

Answer:

58.333%

Step-by-step explanation:

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Best answer gets brainliest!<br><br> What are some equivalent expressions of 6(m + 2 + 7m)?

bezimeni [28]

Answer:

See Explanation

Step-by-step explanation:

To write an equivalent expression, we can combine like terms. So m +7m is 8 and we get 6(8m+2).

Here are a few others:

48m+12

6(m+m+m+m+m+m+m+m+2)

3(16m+4)

6m+12+42m

6m+6m+6m+6m+6m+6m+6m+6m+2

and the list goes on...

3 0

3 years ago

Read 2 more answers

Solve this equation. 25) v - 6(4v + 6) = -82

grin007 [14]

Answer:

$v = 2$

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

$v + -24v + -36 = -82$

Combine 'like' terms:

$(v -24v) + (-36) = -82$

$-23v - 36 = -82$

Next, you'll want to add 36 to both sides of the equation.

$-23v-36 + 36 = -82 + 36$

$-23v = -46$

Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

$v = 2$

I hope this helped you! Leave a comment below if you have any further questions! :)

7 0

3 years ago

Simplify completely 8x^3 ÷ 6x^2 - 4x / -2x

artcher [175]

Answer:

Simplified form is $-(\frac{8x^{3}}{3x-2})$ .

Step-by-step explanation:

The given expression is $8x^{3}\div \frac{6x^{2}-4x}{-2x}$

We can rewrite the given expression as $= 8x^{3}\times (-\frac{2x}{{6x^{2}-4x}})$

Further simplification of the expression gives $=\frac{-16x^{4}}{6x^{2}-4x}$

$=\frac{-16x^{4}}{2x(3x-2)}$

$=-(\frac{8x^{3}}{3x-2})$

So the simplified of the given expression is $=[tex]-(\frac{8x^{3}}{3x-2})$

3 0

3 years ago

Read 2 more answers

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago

I need help on number 36

Ahat [919]

What do you need help with? it helps us to know the question!

8 0

3 years ago

a pair of dice is rolled, what is the probability that the sum is less than 6, given that the sum is 4?​

a pair of dice is rolled, what is the probability that the sum is less than 6, given that the sum is 4?