1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liberstina [14]
3 years ago
14

Ashley has sold 70% of the 20 candy bars she has to. How many candy bar's does she have left to sell

Mathematics
2 answers:
yawa3891 [41]3 years ago
4 0
She has 6 left.
70%= 0.7
0.7 x 20 = how many she has sold (14)
OR
30%=0.3
0.3 x 20= how many she hasn't sold (6)


Nookie1986 [14]3 years ago
3 0
You can use the method: part = percent • whole.
You percent is 70% and whole is 20. Your part is x since that's what you need to find.
You turn 70% into a decimal which is .70, and multiply .70 by 20. This will give you 14, therefore you she sold 14 candy bars. Now you need to subtract how much she sold from how much she needs to sell. 20 minus 14 is 6. She needs to sell 6 more candy bars.
You might be interested in
Gail collects trading cards. Her favorites are baseball and football cards. For
mamaluj [8]
I think it’s c but don’t go with me see if others answer with a different answer :)
8 0
3 years ago
Read 2 more answers
Help me with this exam explanations only
viktelen [127]

the process is coal formation which changes into fossil fuels through burning

4 0
3 years ago
A store is having a going -out-of buisness sale.a television set that orginally cost 3000 has been marked down by30% what do you
allsm [11]

2,247

Step-by-step explanation:

take 3000 and minus that by 30 percent, then after that, add 7 percent to get your total.

7 0
3 years ago
Can anyone help me? My teacher just recently taught me this today, be he never explained much. The question is in the photo
IceJOKER [234]

You've got five different problems in this photo ... four on top and the word problem on the bottom ... and they're all exactly the same thing:  Taking two points and finding the slope of the line that goes through them.

In every case, the procedure is the same.
If the two points are  (x₁ , y₁)  and  (x₂ , y₂) , then
the slope of the line that goes through them is

                          Slope  =  (y₂ - y₁) / (x₂ - x₁) .

This is important, and you should memorize it.

#1).  (8, 10)  and  (-7, 14)

         Slope  =  (14 - 10) / (-7 - 8)  =  4 / -15

#2).  (-3, 1)  and  (-17, 2)

         Slope  =  (2 - 1) / (-17 -  -3)  =  (2 - 1) / (-17 + 3)  =  1 / -14

#3).  (-20, -4)  and  (-12, -10)

         Slope  =  [ -10 - (-4) ] / [ -12 - (-20) ]

=========================================

The word problem:

This question only gives you one point on the graph,
and then it wants to know what's the slope ?
What are you going to do for another point ?

A "proportional relationship" always passes through the origin,
so another point on the line is  (0, 0) .

Now you have two points on THAT line too, and you can easily
find its slope.

4 0
3 years ago
Which property justifies the work shown?
djyliett [7]
Iinnkjnmkjmkjnbhhuhffgytfccvhuuuhjko
3 0
3 years ago
Other questions:
  • What are the coordinates of the x-intercept of the equation -5y=4-2x?
    9·1 answer
  • What is the answer to this?
    15·1 answer
  • Jane borrows $4000 dollars from her bank.she has a simple interest loan at 5% interest rate and will pay it back over 4 years ho
    11·1 answer
  • HEY GUYS PLS HELP ME WITH THIS GEOMETRY QUESTION
    14·1 answer
  • If xy = 0, what must be true about either x or y?
    13·2 answers
  • Based on experimental data, the function T(x) = -3(x − 4)3 + 10 models the temperature of a special substance after being placed
    6·1 answer
  • A candle burned at a steady rate. After 40 minutes, the candle was 12.5 inches. After 70 minutes, the candle was 11.75 inches. U
    6·1 answer
  • Cos x + square root 3 = -cos x
    15·1 answer
  • I need help please help
    10·2 answers
  • The "middle" term of a trinomial form of (3x+1)(x-4) is:
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!