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2 years ago

Please help. :))))))

Mathematics

2 answers:

Fiesta28 [93]2 years ago

7 0

Answer:

6units

Step-by-step explanation:

A=bh

54units^2=9*h

h=54/9

h=6units

Elodia [21]2 years ago

4 0

Answer:

6 because 9 is the length and you only do length times height and 54 divided by 9 is 6 therefore the height is 6

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1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

$m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}$

7 0

2 years ago

A snowstorm began on Monday evening. It snowed steadily until 6:00 am on Tuesday morning when the snow was 12 inches deep. Kevin

poizon [28]

Answer:

what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

Step-by-step explanation:

In this question, we are asked to calculate if the prediction made by an equation modeled is correct.

Firstly let’s look at the equation in question;

y = 3t - 6

where y is the snow depth and t is the number of hours after midnight.

now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.

let’s plug the value of t as 7 into the equation

y = 3(7) - 6

y = 21-6

y = 15 inches

according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

3 0

3 years ago

Determine the length of GH. Round to the nearest tenth. 3.9 cm G 52 642 H

sesenic [268]

Answer:

|GH| = 5,7 cm

Step-by-step explanation:

To know |GH|, you first need to find the length of |GD|.

We can calculate |GD| by;

cosG = |GC| / |GD|

<=> |GD| = |GC| / cosG

=> |GD| = 3,9 cm/ 0,62 = 6,33 cm

We now can easily calculate |GH| with the sinus of angle D;

sinD = |GH| / |GD|

<=> |GH| = sinD.|GD|

=> |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm

I hope i did not make a mistake ...

5 0

3 years ago

Rolling a number less than 4 on a standard number cube *

Molodets [167]

I think it would be a

4 0

3 years ago

Find the coordinates of the midpoint of the segment given its endpoints.

Vesna [10]

Answer:

(2, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{1}{2}$ (x₁ + x₂ ) , $\frac{1}{2}$ (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus

midpoint = [ $\frac{1}{2}$ (5 - 1), $\frac{1}{2}$ (8 - 4 ) ] = (2, 2 )

6 0

3 years ago