Answer:
a) 48.408
b) 1.235
Step-by-step explanation:
a)
The average hardness value xbar can be computed as
xbar=sum of values/number of values
xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12
xbar=580.9/12
xbar=48.408 (rounded to 3 decimal places).
The average hardness value is 48.408.
b)
The standard deviation hardness value s can be computed as
x x-xbar (x-xbar)
²
46.5 -1.90833 3.64174
46.9 -1.50833 2.27507
49.4 0.99167 0.98340
50.3 1.89167 3.57840
49.8 1.39167 1.93674
48.8 0.39167 0.15340
47.0 -1.40833 1.98340
47.7 -0.70833 0.50174
48.3 -0.10833 0.01174
49.4 0.99167 0.98340
47.8 -0.60833 0.37007
49.0 0.59167 0.35007
Total 16.7692
s=1.235 (rounded to 3 decimal places)
The standard deviation hardness value is 1.235.
Answer:
Accept the claim that mean = 8.2oz.
Step-by-step explanation:
Given that a company claims that its coffee cans contain 8.2 ounces of coffee, on average.
To check this, normally large samples are drawn and sample mean is calculated
Then hypotheses created as
H0: Mean = 8.2
Ha: Mean not equals 8.2
The std deviation of sample is found out and then 95% confidence interval is calculated.
If the sample mean falls within 95% confidence interval, then we are 95% confident that for large samples, the sample mean would fall within this interval. Also the claim can be accepted.
Hence conclusion is accept null hypothesis that mean = 8.2 oz.
15,56^2=x^2+x^2
242,1136=2x^2
x^2= 242,1136:2=121, 0568
x≈11,003
<u>False</u>
<em>Like</em><em> </em><em>terms</em><em> </em><em>have the same literal coefficients </em><em> </em><em>but</em><em> </em><em>can have different Numerical Coefficients</em>
Hope this helped you- have a good day bro cya)
