(m.v^2)/ 2 = 25000
<=> 500.v^2 = 50000
<=> v^2 = 100
<=> v = 10 m/s
Answer:
120
240
Step-by-step explanation:
We call the length of first part x
Length of second part = y
In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.
So,
We have this equation,
x/4 + y/3 = 110
We take the LCM
(3x + 4y)/12 = 110
When we cross multiply
3x + 4y = 110x12
3x + 4y = 1320 ----- equation 1
For scenario 2
x/3 + y/4 = 100
When we take the LCM
(4x + 3y)/12 = 100
We cross multiply
4x + 3y = 100x12
4x + 3y = 1200 ------ equation 2
We now have two equations and we will solve for x and y using simultaneous linear equation.
3x + 4y = 1320 ----- 1
4x + 3y = 1200 ----- 2
We subtract equation 2 from 1 to get
- x + y = 120
We make y subject
y = x + 120 ----- 3
We put the value of y in equation 3 into equation 1
3x + 4(x + 120) = 1320
3x + 4x + 480 = 1320
7x + 480 = 1320
7x = 1320-480
7x = 840
We divide through by 7
x = 840/7
x = 120
We put value of x in equation 3
y = x + 120
y = 120 + 120
y = 240
120 and 240 are the lengths of the 2 parts of the journey.
Thanks
Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
<span><span><span>sector area = 9.6944313302
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<span>sector area = 9.7 square meters (rounded)
Source:
http://www.1728.org/radians.htm
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Answer:
Step-by-step explanation:
-4,5
