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Ghella [55]
3 years ago
10

Determine which function has the greatest rate of change over the interval [0, 2].

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0
Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of a:
m= \frac{y_{2}-y_{1}}{x_2-x_1}
m= \frac{4-1}{2-0}
m= \frac{3}{2}
m=1.5
The average rate of change of the function a over the interval [0,2] is 1.5

Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
m=0.5
The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
Here the end points are (0,0.5) and (2,2.5)
m= \frac{2.5-0.5}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function d over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
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Construct a 98% confidence interval to determine whether there is any difference between the mean drug concentration in tablets
inna [77]

Answer:

Step-by-step explanation:

So, we are given two sites;

Site one: 91.28 , 92.83, 89.35, 91.90 82.85, 94.83, 89.83, 89.00, 84.62, 86.96, 88.32, 91.17, 83.86, 89.74, 92.24, 92.59, 84.21, 89.36, 90.96, 92.85, 89.39, 89.82, 89.91, 92.16, 88.67.

=> The mean = add up all the numbers/ the total numbers (which is 25). = 89.55.

=> The standard deviation = 3.005

SITE TWO: 89.35 86.51 89.04 91.82 93.02 88.32 88.76 89.26 90.36 87.16 91.74 86.12 92.10 83.33 87.61 88.20 92.78 86.35 93.84 91.20 93.44 86.77 83.77 93.19 81.79.

=> The mean= add up all the numbers/ the total numbers (which is 25). = 89.033.

=> Standard deviation = 3.271.

NB: the assumption here is that the variance for both sites are the same.

STEP ONE: DETERMINE THE DEGREE OF FREEDOM AND THE CRITICAL VALUE.

The degree of freedom =( mean of site 1 ) + (mean of site 2) - 2 = (25 + 25) − 2 = 48.

Since the degree of freedom is 48, Recall that the value for alpha given = 0.02. Then, the critical value = 2.407.

STEP TWO: DETERMINE THE STANDARD DEVIATION AND THE STANDARD ERROR FOR BOTH.

Therefore, the standard deviation = √[( 25 - 1) × 3.005^2 + (25 -1) × 3.271^2) ÷ (25 +25 - 2) ] = 3.14.

Also, the standard error = standard deviation × ( √(1/ mean 1 + 1/mean 2) ..

Standard error = 3.14 × [ ✓( 1/25 + 1/25)] = 0.89.

STEP THREE: DETERMINE THE CONFIDENCE INTERVAL.

confidence interval = (89.548 - 89.033 - 2.41 × 0.89, 89.548 - 89.033 + 2.41 × 0.89) = (- 1.62, 2.65).

STEP FOUR: THE HYPOTHESES.

=> THE TWO TAILED TEST.

Jo:μ1​ = μ2​.

Ja: μ1​ ≠ μ2​.

Thus, the rejected region is {t : ∣ t ∣ > 2.7}

As critical value = 2.7 for the degree of freedom which is 48 and α=0.01.

If we do the t - test for this,.we will have;

(89.548 - 89.003)÷ ( standard deviation × √ ( 1/25 + 1/25). = 0.58.

So,from our t - value, is less or equals to the critical value, therefore, the null hypothesis is not rejected.

Also, from the p-value table which gives p=0.565. The p- value is greater than or equal to the alpha value(0.01). therefore, the null hypothesis is not rejected.

We are not going to reject the null hypothesis because the information gathered is not enough.

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DaniilM [7]

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2.5 - 5.8n - 4n + 6 =
maxonik [38]

Answer:

Simplify: -9.8n + 8.5

Step-by-step explanation:

2.5 - 5.8m - 4n + 6

  (-5.8n - 4n = -9.8n)

  ( 2.5 + 6 = 8.5)

-9.8n + 8.5

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