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2 years ago

Geometry help last question needing help real bad hope u can please help me 35 point plus brainliest

Mathematics

1 answer:

kherson [118]2 years ago

7 0

We notice that the upper trapezoid is symmetric to the lower one & the line of symmetry should be a horizontal line (mirror line) where any point of the upper vertices should be at equal distance (perpendicular) with the related vertices of the lower one from this horizontal line:
Note that QQ" =4 units, Hence the line of symmetry is the perpendicular to QQ' at 2 units

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PLS HELP <br>find the unknown side of the triangle below (round to the nearest tenth) <br>

Nonamiya [84]

22.9 is the closest but not exact. It was probably rounded off.

I used the formula: leg^2+leg^2=hypotenuse^2

(You can use that formula for any right triangle.)

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3 years ago

a bean plant was 15 centimeters tall one week ago. In 5 days it grew 1 meter. find the current height of the plant.

Likurg_2 [28]

The plant is currently 115 centimeters high

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3 years ago

When we first learn arithmetic, we focus on working with whole numbers. Then, we extend our understanding to fractions and negat

vodka [1.7K]

Answer:

I don't think I can remember every skill I was taught through the years but in Kindergarten we used Number Sense so we could understand the meaning of more and less also there's estimation and PEMDAS. I've also learned how to round up so that the solution is at least around those numbers if the skill is to be applied.

hope that helps

Step-by-step explanation:

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2 years ago

(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim

aleksklad [387]

(i) Given that

$V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr$

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

$V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}$

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

$\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

Compute the integral:

$V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

$V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr$

$V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R$

$V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)$

$V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}$

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0

2 years ago

Convert each percentage into a decimal and match them with the appropriate result.

skad [1K]

Answer:

32% = 0.32

50% = 0.50

34% = 0.34

Step-by-step explanation:

0.32 = 32%

0.50 = 50%

0.34 = 34%

P.S Can I have brainliest?

5 0

2 years ago

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