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3 years ago

Which answer choice is a solution to the equation 0.5x + 3.5 = 6?

Mathematics

2 answers:

kirill [66]3 years ago

7 0

Answer:

x=5

Step-by-step explanation:

Vanyuwa [196]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

leave the x variable on one side:

0.5x = 6 - 3.5

0.5x = 2.5

divide both sides by 0.5:

x = 5

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The length of ZX is 2 units. What is the perimeter of triangle XYZ?

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Keywords

triangle,perimeter,distance, length, side, points

we know that

The perimeter of a triangle is the sum of the three length side

To find the length side calculate the distance between two points

The formula to calculate the distance between to points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step 1

Find the distance ZY

$Z(1,0)\\Y(3,1)$

substitute the values

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Step 2

Find the distance XY

$X(-1,4)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-4)^{2}+(3+1)^{2}}$

$dXY=\sqrt{25}=5\ units$

Step 3

Find the perimeter of the triangle

$P=ZX+ZY+XY$

we have

$dZX=2\sqrt{5}\ units$

$dZY=\sqrt{5}\ units$

$dXY=5\ units$

Substitute

$P=(2\sqrt{5}+\sqrt{5}+5)\ units$

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4 0

3 years ago

Read 2 more answers

Write the first six terms of the geometric sequence with the first term 6 and common ratio 1/3

Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

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