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2 years ago

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Which statement describes a cause of screwed data

1 answer:

Leni [432]2 years ago

8 0

a sample that excludes subjects that are not part of the population being measured.

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It takes Lara 1/3 hour to walk to the library 3/4 mile away. What is her walking pace?

stiv31 [10]

2 1/4 miles per hour.

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2 years ago

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A carpenter purchased 70ft of redwood and 70ft of pine for a total cost of $282. A second purchase, at the same prices, included

dedylja [7]

I think the answer is $2.01 per 1ft of redwood and pine

282/2
=141

$141/70ft ÷ 70/70
=$20.1 per 1ft

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3 years ago

Line segment t and line segment r are parallel. Both line segments are reflected across the y-axis to form line segments t' and

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Answer:/

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Step-by-step explanation:

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2 years ago

Name this polynomial by its degree: 3x² + 5x-3

Stella [2.4K]

Answer:

$\boxed{\textsf {The given polynomial is a quadratic polynomial. }}$

Step-by-step explanation:

A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .

$\sf\implies p(x)= 3x^2+5x-3$

So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .

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When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.

That is ,

$\sf\implies p(x)= 3x^2+5x-3=0$

This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .

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2 years ago

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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ <em> (Approximated)</em>

5 0

2 years ago