Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample proportions for a proportion p in a sample of size n has

In this problem:
- The proportion is of 55%, hence

- The sample has 300 adults, hence

Then, the <u>mean and the standard error</u> are given by:


The probability is the <u>p-value of Z when X = 0.5,</u> hence:

By the Central Limit Theorem



has a p-value of 0.0409.
0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.
A similar problem is given at brainly.com/question/25800303
Answer:
C. Peaches
Step-by-step explanation:
To find the cost of each fruit per pound, divide the cost of the fruit by how many pounds of it there are.
Apples: $6 ÷ 6 = $1
Bananas: $4 ÷ 5 = $0.80
Peaches: $5 ÷ 4 = $1.25
Kiwis: $9 ÷ 6 = $1.50
The type of fruit that has a cost of $1.25 per pound is peaches.
Hope that helps.
Answer: D
Step-by-step explanation:
sinT = Opposite/Hypotenuse
= 13/85
= 0.1529
The answer is (A) Transform energy.
Assuming future value of the principal is required.
P=1400
i=0.06/2=0.03
n=10*2=20
Future value
=P(1+i)^n
=1400(1.03)^30
=2528.56