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vagabundo [1.1K]
3 years ago
5

Witch one is this the answer for I have a lot more questions so stick around if you can help me

Mathematics
1 answer:
tatiyna3 years ago
4 0

-70.04 B would be the correct one

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1)a-19=3 2) y/7=10 3)5g=100 solve please
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Are these three different questions? if so:
1: add 19 to both sides to get a = 3 +19
answer: a = 22

2: multiply both sides by 7 to get y = 10 * 7
answer: y = 70

3: divide both sides by 5 to get g = 100/5
answer: g = 20

hope this helped! good luck :)
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A hospital gives a survey to all surgical patients asking them to rate the quality of their hospital experience. One month after
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The answer is - <span>Some patients who have a poor hospital experience also have post-surgical complications.

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3 years ago
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Find the 76th term of the arithmetic sequence 16, 14, 12, ...<br> I need help pls
Alona [7]

Answer:

<h2>your answer is like this</h2>

Step-by-step explanation:

<h2>a)16. d)-2</h2><h2>an=a+(n-1)d</h2><h2>a76=16+(76-1)-2</h2><h2>=16-150</h2><h2>=-136</h2>
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3 years ago
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Please help.A teacher asked her pupils what their favourite school subject was.
julia-pushkina [17]
Yes this is simple just what is the angle of the whole circle and just subtract from that number.
3 0
3 years ago
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
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