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Setler79 [48]
3 years ago
15

6x+7y=52×-3y=7

%20%3D%207" id="TexFormula1" title="6 \times + 7y = 5 \\ 2 \times - 3y = 7" alt="6 \times + 7y = 5 \\ 2 \times - 3y = 7" align="absmiddle" class="latex-formula">
​

Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

x=2; y=-1

Step-by-step explanation:

Hello,

(1) 6x+7y=5

(2) 2x-3y=7

We multiply equation (2) by 3, it gives

6x-9y=21 and we subtract from (1)

6x-9y-6x-7y=-16y=21-5=16

So y = -1

we replace in (1) 6x-7=5 <=> 6x=7+5=12 <=> x =12/6=2

thanks

Leviafan [203]3 years ago
8 0

Answer:

X = 79/36

Y = -7/6

Step-by-step explanation:

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$29,000 4%decrease<br><br><br><br> 29,000•.04= 1160.00<br><br> 29,000-1160.00=27,840
Rainbow [258]
Yes It would be 27,840
6 0
3 years ago
Geologist has collected 10 specimens of basaltic rock and 10th specimens of granite. The geologist instructs a laboratory assist
olya-2409 [2.1K]

Answer:

p(5)=0.00136

(a) p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

(b)p(10)+p(5)=0.00272

(c)p(7)+p(8)=0.0584

Step-by-step explanation:

If we have N elements with k elements that we consider success and N-k elements that we consider fail, and we take a sample of n elements, the probability that there are x successes in the sample follows a hypergeometric distribution, so it is calculated as:

p(x)=\frac{(kCx)*((N-k)C(n-x))}{NCn}

In this case, N is equal to 20, k is equal to 10 specimens of granite rock, N-k is equal to 10 specimens of basaltic rock and n is 15. So, the probability that there are x specimens of granite rock in the sample or the pmf of the number of granite specimens selected for analysis is:

p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

Now, the probability of getting exactly 5 granite specimens selected for analysis is:

p(5)=\frac{(10C5)*((10)C(15-5))}{20C10}=0.00136

On the other hand, the probability that all specimens of one of the two types of rock are selected  for analysis is the probability to select 10 granite specimens or 10 basaltic specimens. Where the probability to take 10 basaltic specimens is equal to the probability to take 5 granite specimens.

Then, the probability that all specimens of one of the two types of rock are selected  for analysis is:

p(10)+p(5)=\frac{(10C10)*((10)C(15-10))}{20C10}+\frac{(10C5)*((10)C(15-5))}{20C10}\\p(10)+p(5)=0.00136+0.00136=0.00272

For the hypergeometric distribution, the mean E(x) and standard deviation S(x) are:

E(x)=\frac{nk}{N}=\frac{15*10}{20}=7.5\\S(x)=\sqrt{\frac{nk}{N}*(1-\frac{k}{N})*(\frac{N-n}{N-1})}\\S(x)=\sqrt{\frac{15*10}{20}*(1-\frac{10}{20})*(\frac{20-15}{20-1})}=0.9934

Then, the number of granite specimens within 1 standard deviation of its mean value is:

  E(x) - S(x) ≤ mean ≤ E(x) + S(x)

7.5-0.9934 ≤ mean ≤ 7.5+0.9934

     6.5066 ≤ mean ≤ 8.4934

               7 ≤ mean ≤ 8

Finally, the probability that the number of granite specimens selected for analysis is  within 1 standard deviation of its mean value is:

p(7)+p(8)=\frac{(10C7)*((10)C(15-7))}{20C10}+\frac{(10C8)*((10)C(15-8))}{20C10}\\p(10)+p(5)=0.0292+0.0292=0.0584

8 0
4 years ago
NEED HELP ASAP! PLEASE SHOW YOUR WORK!
attashe74 [19]

the answer would be 336 because when you multiply 7x5x9.6 then you you get the total of 336.

6 0
4 years ago
2x2-11x/2-1+y/z<br> if x = 3, y = 7, and z = 2?
Ilya [14]

Answer:

4

Step-by-step explanation:

subsitute the value of the variable into the expression and simplify.

8 0
2 years ago
Can someone please help me!<br> <img src="https://tex.z-dn.net/?f=5%5E%7B-2%7D" id="TexFormula1" title="5^{-2}" alt="5^{-2}" ali
ehidna [41]

In order to do this problem, you must know how to do exponents. You take 5 and divide it by -2. Then your answer is 0.04 or 1/25!


Hope this helped. :)

3 0
3 years ago
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