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gavmur [86]
3 years ago
11

Helpppppppppppppppp (8th)

Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0

Answer:

y=-7

Step-by-step explanation:

if its wrong then i dont  knoowmy teacher gave me this answer.

Goshia [24]3 years ago
3 0
Is that the full screen?
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PSLS ANSWER !!! <<<<<< The quadrilateral in Quadrant II is the image of the quadrilateral in Quadrant IV after
kobusy [5.1K]

Answer:

a . 90⁰

hope it will help you

4 0
2 years ago
50 ÷ (-5) =<br><br><br> Please simplify
mafiozo [28]

Answer:

-10

Step-by-step explanation:

50 ÷ (-5)

First ignore the brackets and the negative sign.

Then divide 50 by 5 to get 10

Then return the negative sign so the answer is; -10

3 0
3 years ago
FRANK has a paper clip.it has a mass of 9g and a volume of 3cm3.what is its density?
Pachacha [2.7K]

Answer:

<h2>3 g/cm³</h2>

Step-by-step explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =   \frac{9}{3}  = 3 \\

We have the final answer as

<h3>3 g/cm³</h3>

Hope this helps you

7 0
2 years ago
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
Given: ΔABC; b= 10; c = 14, and ∠A = 54°. Find the length of side a to the nearest whole number.
alexandr402 [8]
A² = b² + c² - 2bc cosA
a² = 10² + 14² - 2*10*14 cos54
a² = 100 + 196 - 280 * cos54
a = \sqrt{100 + 196 - 280 * cos54}
a = 11.46

5 0
3 years ago
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